If 16 term of an
a.P is -10 and 10 term is -26 then find length 17 term of ap
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Hi mate !!
Here is your answer :
Solution :
Let a be the first term and d be the common difference of the given AP.
Then,
16th term = a + 15d.
But ,
16th term = -10 [ Given ]
a + 15d = -10
a = -10 - 15d -----(1)
And,
10th term = a + 9d.
But ,
10th term = -26 [ Given ]
a + 9d = -26.
Substitute the value of a in equation (2) ,we get
-10 - 15d + 9d = -26
-10 - 6d = -26
-6d = -16
d = 16/6
d = 8/3.
Substitute the value of D in equation (1) ,we get
a = -10 - 15d = -10 - 15 × 8/3.
a = -10 -5 × 8
a = -10- 40 =-50.
Therefore,
17th term = a + 16d = -50 + 16 × 8/3 = -22/3.
Hope it helps you ♥
By rishi403.
BeBrainly.
Here is your answer :
Solution :
Let a be the first term and d be the common difference of the given AP.
Then,
16th term = a + 15d.
But ,
16th term = -10 [ Given ]
a + 15d = -10
a = -10 - 15d -----(1)
And,
10th term = a + 9d.
But ,
10th term = -26 [ Given ]
a + 9d = -26.
Substitute the value of a in equation (2) ,we get
-10 - 15d + 9d = -26
-10 - 6d = -26
-6d = -16
d = 16/6
d = 8/3.
Substitute the value of D in equation (1) ,we get
a = -10 - 15d = -10 - 15 × 8/3.
a = -10 -5 × 8
a = -10- 40 =-50.
Therefore,
17th term = a + 16d = -50 + 16 × 8/3 = -22/3.
Hope it helps you ♥
By rishi403.
BeBrainly.
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