Question

if 162 b is multiple of 3 where b is a digit what are possible value of b​

Answer 1

Step-by-step explanation:

Since 31z5 is a multiple of 3 ,the sum of its digits must be a multiple of 3 i.e. 3+1+z+5=9+z

Hence 9+z is a multiple of 3

Since z is a single digit which can value from 0 to 9

Possible values of z will be,

9+0=9

9+3=12

9+6=15

9+9=18

Thus, there can be four possible values i.e. 0,3,6 or 9

Answer 2

Step-by-step explanation:

31z5 to be a multiple of 3,

3+1+z+5 should be a multiple of 3.

So, the values of z can be 0,3,6 or 9.

If z=0, then the sum is 9.

If z=3, sum is 12

If z=6, sum is 15

If z=9, then the sum is 18

In the above cases, we see that the sums are all multiples of 3.

Hence, z can be 0,3,6 or 9.

thanks me