Question

If 16a^4 + 36a^2b^2 + 81b^4 = 1 and 4a^2 + 9b^2 - 6ab =13 , then what is the value of 3ab?

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

Step-by-step explanation:

use formula i.e.; a⁴+b⁴+a²b² = (a²+b²+ab) x (a²+b² - ab)

a/q

16a⁴+81b⁴+36a²b² = 91 and 4a²+9b² - 6ab = 13 ...........let x

so 4a²+9b²+6ab = 91/13 or 7.......................let y

now x - y gives

-12ab = 13-7 or 6

ab = -1/2

and 3ab = 3 x -1/2 = -3/2 (final answer)