If 18.5 grams of CuCl2 react with 22.8 grams of NaNO3, what mass of NaCl can be formed?
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I think that in question there is mass given of copper nitrate . Because without given mass of second product it is not possible .
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CuCl2+NaNO3=====>CuNO3+Nacl
on balancing
CuCl2+NaNO3===>Cu(NO3)2+2NaCl
find which is limiting reactant
18.5 g copper chloride reacts with 22.8 grams ofq sodium nitrate
limiting reactant calculation is in the picture
answer is 15.678 grams
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