Question

If 180º<θ270º and sinθ= -5/13 then 5cot²θ+12tanθ+13cosecθ= pls tell fast

Answer 1

Step-by-step explanation:

180º<θ270º and sinθ= -5/13 then 5cot²θ+12tanθ+13cosecθ

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180º<θ270º and sinθ= -5/13 then 5cot²θ+12tanθ+13cosecθ

Answer 2

Answer:

answer is zero

Step-by-step explanation:

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