If 18g of glucose is dissolved in 90g of water . Calculate the mole fraction of both components.
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Answer:
Explanation:
Molecular mass of water= 2×1+1×16=18g
=2×1+1×16=18g
For 90g178.2g water n
A =5
Molecular mass of glucose 6×12+12×1+6×16=180g
For 18g glucose n
B =0.1
Now, X
B = 0.1+5 0.1 =0.0196 ~0.02
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