Science, asked by junedkhan6369, 1 year ago

If 19 teams take part in a Single Knock out System Tournament, then how many byes will be given and how many matches will be played?

Answers

Answered by tamoghnamallikarjun3
0

There would be 34 matches played

Answered by amitnrw
3

Answer:

18 Matches played

3 Byes given

Explanation:

19 teams take part in a Single Knock out System

So 9 Matches Beween 18 Teams  +  1  Bye

now there will be 10 Teams

so 5 Matches  + No bye

now There will be 5 Teams

so 2 Matches  + 1 bye

now There will be 3 Teams

so 1 Matches  + 1 bye

now There will be 2 Teams

so 1 Match

Total Matches Played = 9 + 5 + 2 + 1 + 1 = 18 Matches

Total Byes given =  3

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