Physics, asked by poojafugale, 1 year ago

if 1kg of water is mixed with 2kg of liquid of density 3g/cm3 then average density of mixture will be

Answers

Answered by abhi178
12
mass of water = 1 kg
mass of liquid = 2kg
total mass = 1kg + 2kg = 3kg or 3000g

volume of water = mass of water/density of water = 1000g/1g/cm³ = 1000cm³
volume of liquid = mass of liquid/density of liquid
= 2000g/(3g/cm³)
= 2000/3 cm³

total volume of mixture = 2000/3 + 1000
= 5000/3 cm³

now, density of mixture = total mass/total volume
= (3000g)/(5000/3)
= 9/5 = 1.8 g/cm³
Answered by Fatimakincsem
1

Thus the average density of the mixture will be 1.8 g/cm^3

Explanation:

We are given that:

  • Mass of water = 1 Kg
  • Mass of liquid = 2 Kg
  • Density of liquid = 3 g/cm^3

Solution:

Density = Mass/ Volume

1 kg water will be equal to = 1 liter

Density of liquid 3 = Mass / Volume

Therefore volume of liquid = 2 / 3 liter

Total mass of mixture = Mass of water + Mass of liquid =  1 + 2 = 3 kg

Total volume = 1 + 2 / 3 = 5 / 3

Density = 3 / ( 5 / 3 ) = 9 / 5 =  1.8 g/cm^3

Thus the average density of the mixture will be 1.8 g/cm^3

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