if 1kg of water is mixed with 2kg of liquid of density 3g/cm3 then average density of mixture will be
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Answered by
12
mass of water = 1 kg
mass of liquid = 2kg
total mass = 1kg + 2kg = 3kg or 3000g
volume of water = mass of water/density of water = 1000g/1g/cm³ = 1000cm³
volume of liquid = mass of liquid/density of liquid
= 2000g/(3g/cm³)
= 2000/3 cm³
total volume of mixture = 2000/3 + 1000
= 5000/3 cm³
now, density of mixture = total mass/total volume
= (3000g)/(5000/3)
= 9/5 = 1.8 g/cm³
mass of liquid = 2kg
total mass = 1kg + 2kg = 3kg or 3000g
volume of water = mass of water/density of water = 1000g/1g/cm³ = 1000cm³
volume of liquid = mass of liquid/density of liquid
= 2000g/(3g/cm³)
= 2000/3 cm³
total volume of mixture = 2000/3 + 1000
= 5000/3 cm³
now, density of mixture = total mass/total volume
= (3000g)/(5000/3)
= 9/5 = 1.8 g/cm³
Answered by
1
Thus the average density of the mixture will be 1.8 g/cm^3
Explanation:
We are given that:
- Mass of water = 1 Kg
- Mass of liquid = 2 Kg
- Density of liquid = 3 g/cm^3
Solution:
Density = Mass/ Volume
1 kg water will be equal to = 1 liter
Density of liquid 3 = Mass / Volume
Therefore volume of liquid = 2 / 3 liter
Total mass of mixture = Mass of water + Mass of liquid = 1 + 2 = 3 kg
Total volume = 1 + 2 / 3 = 5 / 3
Density = 3 / ( 5 / 3 ) = 9 / 5 = 1.8 g/cm^3
Thus the average density of the mixture will be 1.8 g/cm^3
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