Question

If [1X 2Y 6Z] is a number divisible by 9,then the least value of X+Y+Z is:

Answer 1

Step-by-step explanation:

if the x ,2y ,3z I'd divisible by 9

so least value of x,y,z is 9 only

Answer 2

The least value of "X + Y + Z is zero(0)".

Step-by-step explanation:

We have,

$1^{x}.2^{y}.6^{z}$

To find, the least value of X + Y + Z = ?

∴$1^{x}.2^{y}6^{z}$

Put x = 0, y = - 2 and z = 2

$=1^{0}.2^{-2}.6^{2}$

$=\dfrac{36}{4}$

= 9, is divisible by 9.

∴ X + Y + Z = 0 - 2 + 2 = 0

Hence, the least value of "X + Y + Z is zero(0)".