Question

If 2.0×10^2 gram di nitrogen reacts with 1×10^3 gram di hydrogen to form Ammonia. a. Which is t limiting reagent? b. Calculate the amount of Ammonia formed.

Answer 1

Amount of dihydrogen = 1.00 × 103g. Hence, N2 is the limiting reagent. 28 g of N2 produces 34 g of NH3. Hence, mass of ammonia ...