Question

if√2=1.141,√3=1.732,√5=2.236 find the value of √72+√48

Answer 1

Heya friend,
Here is the answer you were looking for:

$\sqrt{72} + \sqrt{48}$

On splitting we get,

$= \sqrt{2 \times 2 \times 2 \times 3 \times 3} + \sqrt{2 \times 2 \times 2 \times 2 \times 3} \\ \\ = 2 \times 3 \sqrt{2} + 2 \times 2 \sqrt{3} \\ \\ = 6 \sqrt{2} + 4 \sqrt{3}$

Putting the values,

$= 6 \times 1.414 + 4 \times 1.732 \\ \\ = 8.484 + 6.928 \\ \\ = 15.412$

Hope this helps!!!

Feel free to ask in the comment section if you have any doubt regarding to my answer...

@Mahak24

Thanks...
☺☺

Answer 2

Answer :

Given values are -

√2 = 1.414
√3 = 1.732
√5 = 2.236

Now,

√72 + √48

= √(3 × 3 × 2 × 2 × 2) + √(2 × 2 × 2 × 2 × 3)

= (2 × 3)√2 + (2 × 2)√3

= 6√2 + 4√3

= (6 × 1.414) + (4 × 1.732)

= 8.484 + 6.928

= 15.412

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