If √2 = 1.414, find the value of value of √18+2√32 - 3√128 +4√50.
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Answer:
\sqrt{18} + 2 \times \sqrt{32} - 3 \times \sqrt{128} + 4 \div \sqrt{50}
18
+2×
32
−3×
128
+4÷
50
=4.24+2x5. 65-3x11. 31+4x7. 07
=4.24+11.30-33.93+28.28
=15.54-33.93+28.28
=15.54-5.65
=9.89
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