Question

if 2*10 power 8 electrons transfer in 3 sec then what will be the value of current ​

Answer 1

CURRENT= $\frac{2*10^{8}*1.9 *10^{-19} }{3}$

Answer 2

Given:

time t = 3 sec

no of electrons n = 2 × 10⁸

To find:

current I =?

Step-by-step explanation:

• Given that 2 × 10⁸ no of electrons transfer in 3 sec.
• We have to find the value of current.
• We know that,

        $\displaystyle I = \frac{Q}{t}$

       where

       I = value of current ​

      Q = charge

       t = time

• But the charge is the product of no of electrons and charge on an electron.
• The charge on electron is 1.6021 × 10⁻¹⁹ coulombs

         Q = n × q

• So above equation become

        $\displaystyle I = \frac{n \times q}{t}$

       $\displaystyle I = \frac{ 2 \times 10^8 \times 1.6021 \times 10^{-19}}{3}$

        I = 1.068 × 10⁻¹¹

        I = 0.01 × 10⁻⁹

        I = 0.01 nA

• Hence the value of current is 0.01 nA.