Math, asked by harsh110108, 10 months ago

If 2^2n-1=8^3-n, then the value of n is?​

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Answered by Anonymous
7

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Answered by Anonymous
9

 {2}^{2n - 1}  =  {8}^{3 - n}  \\  \\  =  >   {2}^{2n - 1}  =  { ({2}^{3}) }^{3 - n}  \\  \\  =  >  {2}^{2n - 1}  =  {2}^{9 - 3n}

On comparing :

2n - 1 = 9 - 3n

=> 2n + 3n = 9 + 1

=> 5n = 10

=> n = 2

I hope it will be helpful for you ☺️

Fóllòw MË ❤️

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