if 2^2x-y=16 and 2^x+y=32. find x * y answer is 6
Answers
Answered by
2
Given ,
2^( 2 x - y ) = 16
2^ ( 2 x - y ) = 2^4
As bases are equal so exponent must be equal,
2 x - y = 4 -------- eq .1
Now,
2^ ( x + y ) = 32
2 ^ ( x + y ) = 2^5
As bases are equal , so exponent must be equal ,
x + y = 5 ------- eq .2
By adding eq.1 and eq.2,
2 x - y + x + y = 4 + 5
3 x = 9
x = 9 / 3
x = 3.
By substituting the value of x in eq.2,
x + y = 5
3 + y = 5
y = 5 - 3
y = 2.
Now , x * y = 3 * 2 = 6.
Therefore , x*y = 6.
2^( 2 x - y ) = 16
2^ ( 2 x - y ) = 2^4
As bases are equal so exponent must be equal,
2 x - y = 4 -------- eq .1
Now,
2^ ( x + y ) = 32
2 ^ ( x + y ) = 2^5
As bases are equal , so exponent must be equal ,
x + y = 5 ------- eq .2
By adding eq.1 and eq.2,
2 x - y + x + y = 4 + 5
3 x = 9
x = 9 / 3
x = 3.
By substituting the value of x in eq.2,
x + y = 5
3 + y = 5
y = 5 - 3
y = 2.
Now , x * y = 3 * 2 = 6.
Therefore , x*y = 6.
Anonymous:
Thanks Fifa
Similar questions
Math,
9 months ago
Math,
9 months ago
Music,
9 months ago
Political Science,
1 year ago
Science,
1 year ago