If 2^2x+y = 4^x-y-3 = 1, then (x, y) is
a. (-1, -2)
b. (-1, 2)
c. (1, 2)
d. (1, -2)
{ALIGARH MUSLIM UNIVERSITY +2 ENTRANCE TEST 2013-14}
Answers
Answered by
9
2^2x+y=1 and 4^x-y-3=1
2^2x+y=2^0 4^x-y-3=4^0
2x+y=0 x-y-3=0
x=-y/2 -y/2-y=3
(-y-2y)/2=3
-3y=6
y=-2
and x=1
2^2x+y=2^0 4^x-y-3=4^0
2x+y=0 x-y-3=0
x=-y/2 -y/2-y=3
(-y-2y)/2=3
-3y=6
y=-2
and x=1
Answered by
8
HELLO DEAR,
- - - - - - - - - - - 2^(2x+y)=1--------
2^(2X +Y) =2^0
-----------2X + Y = 0------(1)
—-------------4^(x-y-3)=4^0----------
X-y-3=0------------(2)
From (1) and (2)
2x+y=0
X-y=3
-------------------
3x=3
=> x=1
Now put the value of x in (1)
We get,
2*1+ y =0
=>y = - 2
I HOPE ITS HELP YOU DEAR,
THANKS
- - - - - - - - - - - 2^(2x+y)=1--------
2^(2X +Y) =2^0
-----------2X + Y = 0------(1)
—-------------4^(x-y-3)=4^0----------
X-y-3=0------------(2)
From (1) and (2)
2x+y=0
X-y=3
-------------------
3x=3
=> x=1
Now put the value of x in (1)
We get,
2*1+ y =0
=>y = - 2
I HOPE ITS HELP YOU DEAR,
THANKS
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