Math, asked by ashakiran4054, 1 month ago

if [(2/3)^-2]³ × (3/2)^2n = (4/9)², the value of n is​

Answers

Answered by mangasatuluri
5

Answer:

Step-by-step explanation:

(3/2)^6 *(3/2)^2n = (2/3)^4

(3/2)^6 + 2n = (3/2)^-4

6 + 2n = - 4

2n = - 10

n = - 5

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