Question

If 2/3 and -1/2 are solutions of quadratic equation 6x² + ax - b = 0; find the values of a and b
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Answer 1

Answer:

use this

ax^2 + bx + c = 0

sum of roots = -b/a

product of roots = c/a

here roots are given in question

Answer 2

Answer:

$\alpha = \frac{2}{3} \\ \beta = - \frac{1}{2} \\ 6{x}^{2} + ax - b = 0 \\ \alpha + \beta = - \frac{b}{a} \\ \frac{2}{3} +( - \frac{1}{2} ) = - \frac{a}{6} \\ \frac{4 - 3}{6} = - \frac{a}{6} \\ \frac{1}{6} = - \frac{a}{6} \\ a = - 1 \\ \\ \alpha \beta = \frac{c}{a} \\ \frac{2}{3} \times - \frac{1}{2} = \frac{b}{6} \\ \\ \frac{ - 1}{3} = \frac{b}{6} \\ b = - 2 \\ \\ \\ hope \: that \: it \: will \: help \: u$