Question

if 2/3 and -3 are the roots of the equation px²+7x+q=0 ,find the value of the p and q.
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Answer 1

Answer:

$p = \frac{7}{2} and \: q = - \frac{49}{6}$

Step-by-step explanation:

$sol {}^{n}$

$px {}^{2} + 7x + q \: = 0$

the roots of the equation are 2/3 and -3

So,

$\frac{2}{3} \times ( - 3) = - \frac{7}{p} and \: \frac{2}{3} + ( - 3) = \frac{q}{p}$

$now \: \: \frac{2}{3} \times ( - 3) = - \frac{7}{p}$

$= > - 2 = - \frac{7}{q}$

$= > q = \frac{7}{2}$

Again

$\frac{2}{3} + ( - 3) = \frac{q}{p}$

$= > \frac{2 - 9}{3} = \frac{q}{p}$

$= > \frac{ - 7}{3} = \frac{q}{p}$

$= > q = p \times \frac{ - 7}{3}$

$= > q = - \frac{7}{3} \times \frac{7}{2}$

$so \: \: q = - \frac{49}{6}$