Question

The area of the triangle formed by the points P(4,0), Q(6,0) and R(6, 8) is 4 sq. units 8 sq. units 12 sq. units 16 sq. units​

Answer 1

Answer:

8 sq unit

Step-by-step explanation:

Area = 1/2 { x1(y2-y3) +x2(y3-y1) +x3(y2-y1)}

=1/2 {4(0-8)+6(8-0)+6(0-0)}

=1/2 { - 32+48}

=1/2( 16)

=8

Answer 2

Given:

P(4,0), Q(6,0) and R(6, 8)

To find :

The area of the triangle.

Formula to be used:

Area of a triangle = $\frac{1}{2} [x_{1} (y_{2} - y_3)+x_{2} (y_{3} - y_1)+x_{3} (y_{2} - y_1)]$

Solution:

Let,

$x_1 = 4 , y_1 = 0\\x_ 2 = 6 , y_2 = 0\\x_3 = 6 , y_3 = 0$

Area of a triangle = $\frac{1}{2} [x_{1} (y_{2} - y_3)+x_{2} (y_{3} - y_1)+x_{3} (y_{2} - y_1)]$

Area of a triangle = $\frac{1}{2} [4(0-8)+6(8-0)+6(0-0)]$

Area of a triangle = $\frac{1}{2} [-32+48+0]$

Area of a triangle = $\frac{1}{2} [16]$

Area of a triangle = 8 sq. units

Final answer:

The area of the triangle formed by the points P(4,0), Q(6,0) and R(6, 8) is

8 sq. units.