Question

If 2,3 are two zeros of x^3-5x^2+6x, then find third zero.

Answer 1

Answer:

x*3-5x*2+6x=0

take x as common,

x(x*2-5x+6)=0

x(x-3)(x-2)=0

x=0,(x-2)=0,(x-3)=0

therefore the third zero is 0

therefore the obtained zeroes are 0,2,3