if 2/3 exceeds its3/5by 1 ,find te no
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The equation is (3/5)xn + 1 = 2/3
On solving we get x = -5/9
On solving we get x = -5/9
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Let the number be x.
(2/3)x=(3/5)x+1
1=(2/3)x-(3/5)x
on solving,
x=15.
(2/3)x=(3/5)x+1
1=(2/3)x-(3/5)x
on solving,
x=15.
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