Question

if 2/3 is a root of the equation Kx^2-x-2=0, then what is the value of k?

Answer 1

put the value of x in equation as 2/3

k(2/3)^2-2/3-2=0

[4/9]k-2/3-2=0

then lcm of 3 and 9 is 9

therefore

4k-6-18/9=0

4k-24/9=0

4k-24=0

4k=24

k=24/4

k=6