Question

If (2,3) lies on the graph of the like (k+1)x-(2k+3)y-1=0 then find the value of k.

Answer 1

Answer:

k = -2

Step-by-step explanation:

If (2,3) lies on the line then it must satisfy the equation of line.

(k+1)(2)-(2k+3)(3)-1 =0

2k+2-6k-9-1 =0 => 4k = -8 => k = -2