Question

if (2/3)^x-8=(8/27)^4-3x find the value of x​

Answer 1

Answer:

(2 \3) ^{x - 8} = (8 \ 27) ^{4 - 3x }

(2 \ 3) ^{x - 8} = (2 \3)^{3 (4 - 3x)}

(2 \ 3) ^{x - 8} = (2 \3) ^{12 - 3x}

base are same exponets are equal

x - 8 = 12 - 3x

x + 3x = 12 + 8

4x = 20

x = 5