Math, asked by Sayanthmohan, 7 months ago

If 2, 3k - 1, 8 are in A.P. then what is the value of k?

Answers

Answered by rajdheerajcreddy

2

Answer:

2.

Step-by-step explanation:

Given that, 2 , 3k-1,8 are in A.P.

So, 2(3k-1) = 2+8

=> 6k-2 = 10

=> 6k = 12

=> k = 2.

Answered by HimanshuMahiya

3

Answer:

k=2

Step-by-step explanation:

a=2, d=t2–t3

3k–1–2=8–(3k–1)

3k–3 =8–3k+1

3k+3k. =9+3

6k. = 12

thus, k=. 12/6

= 2

I hope you understand

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