Question

if 2/5 of a number exceeds 1/7 of the same number by 36 .find the number

Answer 1

Solution: Let the number is x
then 2/5 of x=2x/5
x exceeds 1/7 of number 36

there for the equation 2x/5=x/7+36
2x/5-x/7-36=0
9(x-140)/35=0

x=140

the number is 140. :)

Answer 2

Hi there !!

Let the number be x

2/5th of the number = 2x/5

1/7th of a number = 1x/7 or x/7

Given that,
2/5 of a number exceeds 1/7 of the same number by 36

So,
the following balanced equation will be formed

$\frac{2x}{5} = \frac{x}{7} + 36$

transposing x/7 to LHS,
we have,

$\frac{2x}{5} - \frac{x}{7} = 36$
Taking LCM as 3



$\frac{14x - 5x}{35} = 36$


$\frac{9x}{35} = 36$

$x = \frac{36 \times 35}{9}$
x = 140

Thus,
the number is 140