IF 2^a = 3^b = 6^c, then find the relation between a, b and C.
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Answer:
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Answered by
0
Let 2a = 3b = 6c = k
2a = k
2 = \frac{k}{a}2=
a
k
3b = k
3 = \frac{k}{b}3=
b
k
6c = k
6 = \frac{k}{c}6=
c
k
We know that,
6 ÷ 3 = 2
\frac{k}{c} \div \frac{k}{b} = \frac{k}{a}
c
k
÷
b
k
=
a
k
\frac{k}{c} \times \frac{b}{k} = \frac{k}{c}
c
k
×
k
b
=
c
k
\frac{b}{c} = \frac{k}{a}
c
b
=
a
k
[k = 6c]
b/c = 6c/a
b(a) = 6c(c)
ab = 6c²
ab/c² = 6
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