if 2(a²+b²) = (a+b)². show that a=b
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here is your answer.
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VishnuPratap:
good explanation
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Hey friends!!
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Here is your answer↓
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To prove:- 2(a²+b²)= (a+b)² => a=b.
→ 2(a²+b²)=(a+b)².
=> 2[(a+b)²-2ab]=(a+b)²
=> 2(a²+b²+2ab-2ab)= a²+b²+2ab.
=> 2a²+2b²=a²+b²+2ab.
=> 2a²-a²+2b²-b²=2ab.
=> a²+b²-2ab=0.
=> (a-b)²=0. [a²+b²-2ab=(a²-b²).
=> a-b=√0.
=> a-b=0.
=> a=b.
Hence ,it is proved.
☺☺☺ Hope it is helpful for you ✌✌✌.
--------------------------------------------
Here is your answer↓
--------------------------------------------
To prove:- 2(a²+b²)= (a+b)² => a=b.
→ 2(a²+b²)=(a+b)².
=> 2[(a+b)²-2ab]=(a+b)²
=> 2(a²+b²+2ab-2ab)= a²+b²+2ab.
=> 2a²+2b²=a²+b²+2ab.
=> 2a²-a²+2b²-b²=2ab.
=> a²+b²-2ab=0.
=> (a-b)²=0. [a²+b²-2ab=(a²-b²).
=> a-b=√0.
=> a-b=0.
=> a=b.
Hence ,it is proved.
☺☺☺ Hope it is helpful for you ✌✌✌.
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