Question

if 2 and 0 are the zeros of polynomials f(x)=2x^3-5x^2+ax+b then find the values of a and b hints:f(2)=0 f(0)=b​

Answer 1

Answer:

Step-by-step explanation:

f(2)=2×2^3-5×2^2+a×2+b=0

=16-20+2a+b=0

= -4+2a+b=0

=2a+b=4

=b=4-2a.........(i)

now,

f(0)=2×0^3-5×0^2+a×0+b=0

=b=0

=4-2a=0

=4=2a

=4/2=a

a=2

putting value of (a) in (i)

b=4-2×2

b=4-4

b=0

Answer 2

Answer:

the value of a=2

the value of b=0

Hope it will help you