If 2 and-3 are the zeroes of the polynomial x2+(a+1)x+b,then find the values of a and b
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Step-by-step explanation:
x=2
=(2)2+(a+1)(2)+b
=4+(2a+2)+b
=4+2a+2+b
0=6+2a+b
-6=2a+b........[1]
x=3
=3×3+a+1×2+b
=9+2a+3+b
0=12+2a+b
-12=2a+b.......[2]
solve it
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