मान लीजिए कि f, g तथा h, R से R तक दिए फलन हैं। सिद्ध कीजिए कि(f + g) oh = foh + goh(f.g) oh = (foh). (goh)
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Step-by-step explanation:
सिद्ध करना है -
(f + g) oh = foh + goh(f.g) oh = (foh). (goh)
∀ x ∈ R
{ (f+g) oh) (x) = ( f+g) (h(x))
= f (h(x)) + g (h(x))
= ( foh) (x) + ( goh ) (x)
= ( foh + goh ) (x)
⇒ (f+g)oh = foh + goh
पुनः ∀ x ∈ R
((f.g) (x) = (f.g) (h(x)) = f(h(x)) g (h(x))
= {(foh) (x)}. {(goh) (x)}
= { (foh). (goh)} (x)
⇒ (f.g) oh = ( foh) . (goh)
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