If 2 and -3 are the zeroes of the quadratic polynomial xsquare+(a(1)x+b then find the value of a
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sum of zeroes= -1=-a
product of zeroes =-6
hence the value of a is 1
product of zeroes =-6
hence the value of a is 1
Answered by
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Heya!
Here is yr answer.....
Given,
=> x² + ax + b
2 and -3 are the zeros of the polynomial of the above equation
Therefore,
(2)² + a(2) + b = (3)² + a(3) + b
4 + 2a + b = 9 + 3a + b
2a - 3a + b - b = 9 - 4
-a = 5
a = -5
Substitute, a value in the equation....
eq. x² + ax + b = 0
(2)² + -5(2) + b = 0
4 - 10 + b = 0
-6 + b = 0
b = 6
a = -5 , b = 6
Hope it hlpz..
Here is yr answer.....
Given,
=> x² + ax + b
2 and -3 are the zeros of the polynomial of the above equation
Therefore,
(2)² + a(2) + b = (3)² + a(3) + b
4 + 2a + b = 9 + 3a + b
2a - 3a + b - b = 9 - 4
-a = 5
a = -5
Substitute, a value in the equation....
eq. x² + ax + b = 0
(2)² + -5(2) + b = 0
4 - 10 + b = 0
-6 + b = 0
b = 6
a = -5 , b = 6
Hope it hlpz..
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