Question

If 2 and -3 are the zeroes of the quadratic polynomial x2+(a+ 1) x+b; then find the values of a. please answer before 7 pm

Answer 1

Step-by-step explanation:

I think it is useful to you

Answer 2

Answer:

a= 0

0b= - 6

Step-by-step explanation:

2 is zero of polynomial x^2+(a+ 1) x+b

so at x=2 it gives value zero

(2)^2+ (a+1)× 2 + b=0

4+2a+2+b=0

2a+b= -6 ---------> (1)

Again at x= -3 polynomial will be zero

(-3)^2+ (a+1)× (-3) +b =0

9- 3a-3+b= 0

-3a + b = -6 --------> (2)

solving equations 1 and 2

2a+ b= -3a+b

5a = 0

so a= 0

putting a= 0 in equation 1

We get b= -6

a=0

b= -6