Math, asked by Anonymous, 1 month ago

If 2 and -3 are the zeroes of the quadratic polynomial
x2 + (a + 1)x + b; then find the values of "a" ?

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Answers

Answered by samaira173
1

Answer:

a=0 and b=-6

Step-by-step explanation:

when x=2

2^2 + 2(a+1)+b=0

4+2a+b=0

6 +2a +b = 0

2a+b=-6       (1)

when x=-3

3^2 + -3(a+1) + b = 0

9-3a-3+b=0

6-3a+b = 0

b-3a = -6        (2)

from (1) and (2),

2a+b=b-3a

2a+3a=b-b

5a=0

a=0/5

a=0

b-3a=-6

b-0=-6

b=-6

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