Question

if -2 and 3 are the zeroes of x²+(a+1)x+b. then find a and b. *explain in proces*​

Answer 1

Answer:

-2*2+a+1-2+b

4+2a-2+b

2+2a+b

3*2+a+1*3+b

9+3a+3+b

12+3a+b

3(2+2a+b)

2(12+3a+b)

6+12a+3b

24+12a+2b

-. -. -

18+b

b=-18

12a+3b+6

12a-54+6

12a=48

a=4

Answer 2

Answer:

p(-2) =(-2) ^2+(a+1) -2+b

=4-2a-2+b

= -2a+b+2 ------equation 1

p(3) =9+3a+3+b

=3a+b+12 ------equation2

subtracting equation 1 from 2

5a= -10

a= -2

putting value of a in equation

3x-2+b= -12

-6+b= -12

b= -6