If -2 and 3 are the zeros of the quadratic polynomial x2 + (a + 1)x + b then find value of a and b
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Answer:
a=-2
b=18
Step-by-step explanation:
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Given polynomial:
- x² + (a + b)x + b
Given zeroes:
- -2 and 3
Sum of zeroes:
→ -2 + 3
→ 1
Product of zeroes:
→ -2 × 3
→ -6
We know that -
Sum of zeroes = -b/a
→ 1 = -(a + 1)/1
→.-a - 1 = 1
→ -a = 1 + 1
→ -a = 2
→ a = -2
Also, product of zeroes = c/a
→ -6 = b/1
→ b = -6
Hence, value of a and b are -2 and -6 respectively.
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