If -2 and 3 are the zeros of thw quadratic polynomial x square +(a+1)x+b find the value of a and b
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Step-by-step explanation:
sum of roots is = -( coeff. of x)/ coeff. of x^2
therefore,
-(a+1) = -(-1)
a+1 = -1
a = -2
product of roots = constant / coeff. of x^2
b = (-2)(3)
b = -6
munir12:
sry ra....a correction sum of roots is 1 (-2+3=1) but i substituted -2
now its ryt
gr8
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