if 2 and -3 are zeros of polynomial x3 +ax2 +bx-12 find the values of a and b
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2^3 +a*2^2 + b*2 -12
0=8+4a+2b-12
0=-4+4a+2b
4=2(2a+b)
2=2a+b
2-2a=b ...............(1)
0=-3^3+a*-3^2+b*-3-12
0=27+9a-3b-12
0=35+9a-3b
-35=9a-3(2-2a)
-35=9a-6+6a
-35+6=15a
-29=15a
-29/15=a
....hope it helps
0=8+4a+2b-12
0=-4+4a+2b
4=2(2a+b)
2=2a+b
2-2a=b ...............(1)
0=-3^3+a*-3^2+b*-3-12
0=27+9a-3b-12
0=35+9a-3b
-35=9a-3(2-2a)
-35=9a-6+6a
-35+6=15a
-29=15a
-29/15=a
....hope it helps
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