Question

if 2 and -3 are zeros of x2 +(a+b) + b then find a+b

Answer 1

Answer:

Given,

• p(x) =x² + (a+b)x + b
• zeros → 2 and -3

To find:—

• → a + b

$We \: \: know \: \: that ,$

$For \: \: any \: \: p(x) → \underline \bold{ax² + bx + c}$

$\boxed{→ Sum \: \: of \: \: zeros = \: \bold{ \mathtt{\frac{ - b}{a} }}}$

So,

$2 + ( - 3) = \frac{ - (a + b)}{1}$

$\implies \: - 1 = - (a + b)$

$\implies \: \large\boxed{ \mathtt{ \color{red}{ \bold{a + b = 1}}}}$

Answer 2

Answer:

sum of roots=-b/a

=>2+(-3)=-(a+b)/1

=>-1=-1(a+b)

a+b=1