Question

If-2 and the 3 are
the zeroes of the polynomial
ax²+bx-6, then find the value of a and b​

Answer 1

Answer:

we have a quadratic polynomial,

let p(x)= ax²+bx-6

Also, (-2) and 3 are its two zeros,

then, let u= -2 and v= 3

For a quadratic polynomial,we know that

sum of the zeros =

-Coefficient of x / coefficient of x²

Then,

u+v= -b/a

(-2)+3=-b/a

-b/a=1

so, -b=a..... ...............I

Also, Product of the zeros=

Constant term/ coefficient of x³

then,

u×v= -6/a

(-2)×3=-6/a

-6=-6/a

so, a=1

From EQ.I. we have

-b=a

b=-a

b = -1

Hence, a=1. and. b=(-1)