Math, asked by nathanchetna386, 2 months ago

If -2 and three are the zeros of quadratic polynomial X square plus a plus 1X plus B then

Answers

Answered by pulakmath007
2

SOLUTION

GIVEN

- 2 & 3 are the zeros of quadratic polynomial

 \sf{ {x}^{2}  + (a + 1)x + b}

CONCEPT TO BE IMPLEMENTED

If the Sum of zeroes and Product of the zeroes of a quadratic polynomial is given then the quadratic polynomial is

 \sf{ {x}^{2}  -(Sum  \: of \:  the \: zeroes )x +  Product \:  of  \: the \:  zeroes }

TO DETERMINE

The value of a and b

EVALUATION

Here it is given that

- 2 & 3 are the zeros of quadratic polynomial

Then the quadratic polynomial is

 \sf{ {x}^{2}  -(Sum  \: of \:  the \: zeroes )x +  Product \:  of  \: the \:  zeroes }

 \sf{ =  {x}^{2} - ( - 2 + 3)x + ( - 2 \times 3) }

 \sf{ =  {x}^{2} - x + 6}

Again the given Quadratic polynomial is

 \sf{ {x}^{2}  + (a + 1)x + b}

Comparing we get

a + 1 = - 1 & b = 6

⇒ a = - 2 & b = 6

FINAL ANSWER

Hence the required value of a and b are - 2 & 6 respectively

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