if 2 angle a = 3 angle c= 6 angle c .then find angle a ,b,c
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2 /_ A = 3 /_ B = 6 /_ C
Let 2 /_ A = 3/_ B = 6/_ C = X° . Then,
/_ A = ( X/2)° , /_ B = ( X/3)° and /_ C = (X/6)°
Therefore,
X/2 + X/3 + X/6 = 180 [ Since /_ A + /_ B + /_ C = 180° ]
3X + 2X + X = 1080
6X = 1080
X = 1080/6
X = 180°.
__________________________
/_ A = ( X/2)° = (180/2) = 90°
/_ B = ( X/3)° = (180°/3) = 60°
and,
/_ C = (X/6)° = (180/6)° = 30°
Let 2 /_ A = 3/_ B = 6/_ C = X° . Then,
/_ A = ( X/2)° , /_ B = ( X/3)° and /_ C = (X/6)°
Therefore,
X/2 + X/3 + X/6 = 180 [ Since /_ A + /_ B + /_ C = 180° ]
3X + 2X + X = 1080
6X = 1080
X = 1080/6
X = 180°.
__________________________
/_ A = ( X/2)° = (180/2) = 90°
/_ B = ( X/3)° = (180°/3) = 60°
and,
/_ C = (X/6)° = (180/6)° = 30°
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