Question

If 2 balls are drawn at random one after another from a box containing 3 red and 6 blue balls,what is the probability that the first ball is blue and second ball is red

Answer 1

may be it is helpful

Answer 2

Answer:

The probability of the first ball is blue and second ball is red is  $\frac{1}{4}$

Step-by-step explanation:

Number of red balls = 3

Number of blue balls = 6

Total number of balls = 3 + 6 = 9

We need to find the probability of having first blue ball and then red ball

We know that Probability = $\frac{No. of favourable outcomes}{Total no. of outcomes}$

After drawing a blue ball, the number of balls in the box = 9 - 1 = 8

Therefore required probability = P(Blue Ball) * P(Red Ball)

                                                   = $\frac{6}{9}$ *  $\frac{3}{8}$

                                                   = $\frac{1}{4}$

Therefore, the probability of the first ball is blue and second ball is red is  $\frac{1}{4}$