the radius of a sphere is 5.3+ or - 1.3 cm calculate %error in its volume
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Assuming the measurements is of a sphere.
Volume of sphere is calculated by formula
V=43πr3
Log on both sides
Log V=log (43π) + 3logr
If ΔV and Δr are respective errors in volume and radius, from theory of errors we see that
ΔVV=3Δrr
Putting all values
ΔVV=3×±0.15.3=±0.0566
= ±5.7, rounding up to one decimal point
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Volume of sphere is calculated by formula
V=43πr3
Log on both sides
Log V=log (43π) + 3logr
If ΔV and Δr are respective errors in volume and radius, from theory of errors we see that
ΔVV=3Δrr
Putting all values
ΔVV=3×±0.15.3=±0.0566
= ±5.7, rounding up to one decimal point
Mark the answer as brainliest if it helped
Thank you
Read more on Brainly.in - https://brainly.in/question/1183491#readmore
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