solve the equation using the method of substitution 3 x - 5 y = - 1 and x - y = - 1
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x = y -1
now substituting in 3x-5y=-1
3(y-1)-5y=-1
3y-3-5y=-1
y=-1
now putting y in x = y - 1
we get x=-2
now substituting in 3x-5y=-1
3(y-1)-5y=-1
3y-3-5y=-1
y=-1
now putting y in x = y - 1
we get x=-2
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