Question

If 2 is 0 of x3 -4x2 + kx - 8

Answer 1

Answer:

Putting the value 2 in x (as it is a zero)

p(2)=$2^{3} -8+2k-8$

as 2 is a zero, $2^{3} -8+2k-8$ should be equal to zero.

So,

⇒$2^{3} -8+2k-8 = 0$

⇒8 - 8 + 2k - 8 = 0

⇒2k - 8 = 0

⇒2k = 8

⇒k = 4

Please mark this as brainliest!

Answer 2

p(x) =2

(2×3)-(4×2×2)+(k×2)-8

6-16+k2-8

-6+k2-8

k2=8+6

K2=14

K=7