If-2 is a common root of the equation ax2-ax+6=0 and x2-x+b=0,find 'a'and 'b'
Answers
Step-by-step explanation:
ax^2+ax+6=0
a(-2)^2+a(-2)+6=0
a(4)-2a=-6
4a-2a=-6
a=-6/2
a=-3
now b
x^2-x+b=0
(-2)^2+(-2)+b=0
4-2+b=0
2+b=0
b=2
a=-3
b=2
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Answer:
The value a = -1 and the value of b = -6
Step-by-step explanation:
Given equations ax² - ax + 6 = 0 _(1)
x² - x + b = 0 _(2)
and common root of the equations is - 2
here we need to find the values of a and b
substitute x = -2 in (1)
(1) ⇒ a(-2)² - a(-2) + 6 = 0
4a + 2a + 6 = 0
6a + 6 = 0
6a = -6
a = -1
substitute x = -2 in (2)
(2) ⇒ (-2)² - (-2) + b = 0 _(2)
4 + 2 + b = 0
6 + b = 0
b = - 6
the value a = -1 and the value of b = -6