Question

if 2 is a root of ax2+ kx+2a=0 then the other root​

Answer 1

Answer:

the answer to this question is x²+12=0

Step-by-step explanation:

root of the above ewuation is 2 2²+k(2)=0

4+2k+12=0

2k=-16

k=-8

x²+kx+q=0

x²-8x+q=0

condition of equal roots is b²=4ac

(-8)²=4(1)(q)

9=16