Question

If A²+B²C² = 6400 and A+B+C = 20, then values of A, B and C

Answer 1

Answer:

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(a + b + c)² = a² + b² + c² + 2ab + 2bc + 2ca

(a+b + c)² = a² + b² + c²+2 (ab + bc + ca)

(20)2 = 90+2 (ab + bc + ca)

400-90= 2 (ab + bc + ca)

310/2 = ab + bc+ ca

ab + bc + ca = 155

Answer 2

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( a+ b + c) 2 = a2 + b2 + c2 + 2 ( ab + bc + ac)

ab + bc + ac = --20 / 2 = -10